Question

помогите
x(x-1)(x+5)=(x+3)^2(x-2)

Answer 1

x(x-1)(x+5)=(x+3)^2(x-2)

(x^2-x)*(x+5)=(x+3)^2*x-(x+3)^2*2

x^3+5x^2-x^2-5x=(x^2+6x+9)x-(x+3)^2

x^3+5x^2-x^2-5x=x^3+6x^2+9x-(x+3)^2

5x^2-x^2-5x=6x^2+9x-(x^2+6x+9)*2

4x^2-5x=6x^2+9x+(-x^2-6x-9)*2

4x^2-5x=6x^2+9x-2x^2-12x-18

4x^2-5x=4x^2-3x-18

-5x=-3x-18

-5x+3x=-18

-2x=-18

x=9