Question

решите систему {х-у=1 х²-у=3

Answer 1

x = y + 1
(y + 1)^2 - y = 3*

*y^2 + 2y + 1 - y - 3 = 0
y^2 + y - 2 = 0 
D = 1 + 8 = 9 
y1 = ( - 1 + 3)/2 = 1
y2 = ( - 1 - 3)/2 = - 2

x1 = y1 + 1 = 1 + 1 = 2
y1 = 1

x2 = y2 + 1 = - 2 + 1 = - 1
y2 = - 2 

Ответ
( - 1 ; - 2)  
(2; 1)