Предмет: Физика, автор: Натали996

Сопротивление волоска лампы накаливания 50 Ом, сопротивление подводящих проводов 0,4 Ом. Определить падение напряжения на лампе накаливания и напряжение в подводящих проводах, если по ним проходит ток 2 А.

Ответы

Автор ответа: Аноним

напряжение на лампе равно U=I*R1=2*50=100B

напряжение проводов равно U=I*R2=2*0,4=0,8B)))

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