Question

Найти интеграл arcsin 8x dx

Answer 1

= x arcsin(8x) - ∫ 8x dx/√(1 - 64x^2)
= x arcsin(8x) - (1/16) ∫ 128x (1 - 64x^2)^(-1/2) dx
= x arcsin(8x) - (1/16) * 2(1 - 64x^2)^(1/2) + C
= x arcsin(8x) - (1/8) √(1 - 64x^2) + C.