Question

Помогите(((( Найти производную сложной функции 

Answer 1

$\y=frac{(sqrt{x}-1)^2}{x}\ y'=frac{2(sqrt{x}-1)cdot (frac{1}{2sqrt{x}}-0)cdot x-(sqrt{x}-1)^2cdot1}{x^2}\ y'=frac{(sqrt{x}-1)(frac{x}{sqrt{x}}-sqrt{x}+1)}{x^2}\ y'=frac{(sqrt{x}-1)(frac{xsqrt{x}}{x}-sqrt{x}+1)}{x^2}\ y'=frac{(sqrt{x}-1)(sqrt{x}-sqrt{x}+1)}{x^2}\ y'=frac{(sqrt{x}-1)cdot1}{x^2}\ y'=frac{sqrt{x}-1}{x^2}$