Question

представьте квадрат двучлена в виде многочлена
1 (10а^2-p^4)^2

2 (15k^4+13)^2

3 (11+6p)^2

4 (n^2-1)^2

5 (5d+1)^2

Answer 1

1 (10а^2-p^4)^2=100a^4-20a^2p^4+p^8

2 (15k^4+13)^2=225k^8+390k^4+169

3 (11+6p)^2=121+132p+36p^2

4 (n^2-1)^2=n^4-2n^2+1

5 (5d+1)^2=25d+10d+2