Question

решить уравнение
[x+2]^2/6-x^2--4/4+[x-2]^2/12=2

Answer 1

[x+2]^2/6-x^2--4/4+[x-2]^2/12=2
3/4*x^2+1/3*x=0
x(1,2)=0,(-1/3)/(-3/4)=0,(4/9)