Question

6^cosx=0.5^sinx*3^cosx

Answer 1

6^cosx=2^cosx*3^cosx

2^cosx*3^cosx=2^-sinx*3^cosx

2^cosx=2^-sinx

cosx=-sinx

cosx+sinx=0

/ на cosx не= 0

1+tgx=0

tgx=-1

x=3pi/4+2(pi)f

x=7pi/4+2(pi)d

d,f принадлежат Z