Question

СИСТЕМА
2 x^{2} +3 y^{2}=11,
4 x^{2} +6 y^{2} =11x

Answer 1

2х^2 + 3у^2 = 11
4х^2 + 6у^2 = 11х
Решение
- 4х^2 - 6у^2 = - 22
- 4х^2 + 4х^2 - 6у^2 + 6у^2 = - 22 + 11х
0 = - 22 + 11х
11х = 22
Х = 2
2•2^2 + 3у^2 = 11
3у^2 = 11 - 8
3у^2 = 3
у1 = 1
у2 = - 1
Ответ ( 2 ; 1 ) ; ( 2 ; - 1 )