Question

$4x^4+3x^3+32x+24=0$

Найти корни?

Answer 1

$4x^4+3x^3+32x+24=0\ 4x(x^3+8)+3(x^3+8)=0\ (4x+3)(x^3+8)=0\ 4x+3=0 x^3+8=0\ x=-0,75 x=-2$

Ответ:{-2;-0,75}

Answer 2

4x(x^3+8) +3(x^3+8)=0

(4x+3)(x^3+8)=0

4x+3=0

4x=-3

x=-3/4

 

x^3+8=0

x^3=-8

x=-2