Question

найдите значение функции f (x) = x^2 +1 при х = 3; -4; 0; 5.

Answer 1

f(3)=3^2+1=9+1=10; f(-4)=(-4)^2+1=16+1=17; f(0)=0^2+1=1; f(5)=5^2+1=25+1=26.