Question

(a+6)(a-2)-(a-7)(a+1) при a=0,51

Answer 1

$a=0,51\\(a+6)(a-2)-(a-7)(a+1)=(a^2+4a-12)-(a^2-6a-7)=\\=10a-5=5(2a-1)=5(2cdot 0,51-1)=5cdot 0,02=0,1$