Question

Найти первообразную $sqrt{x}$

Answer 1

$f(x)= sqrt{x} \ F(x)= intlimits {x^{1/2}} , dx = frac{x^{3/2}}{ frac{3}{2} } +C= frac{2x^{3/2}}{3} +C\ F(x)= frac{2}{3} x^{3/2}+C$