Question

1)25x^2-10xy+y^2-9. 2)ay^7+y^7-ay^3-y^3. Разложить на множители

Answer 1

$25x^2-10xy+y^2-9=(5x-y)^2-3^2=(5x-y+3)(5x-y-3)$

$ay^7+y^7-ay^3-y^3=y^7(a+1)-y^3(a+1)=y^3(a+1)(y^4-1)=\ \ =y^3(a+1)(y^2-1)(y^2+1)=y^3(a+1)(y-1)(y+1)(y^2+1)$