Question

x+y/3+3x-5y/2=2
(x+3)(y+2)=xy+35

 

 

 

x-1/2-y+1/3=2
(x-5)(y-3)=xy -58

Answer 1

$x+frac{y}{3}+3x-frac{5y}{2}=2 \ (x+3)(y+2)=xy+35 \ 6x+ 2y+18x-15y=12 \ xy+2x+3y+6=xy+35 \ 24x-13y=12 \ 2x+3y= 29 |times (-12) \ 24x-13y=12 \ -24x-36y= -348 \ -49y=-336 \ y=6 frac{42}{336}=6 frac{1}{8} \ 24х-13(6 frac{1}{8})=12 \ y=6 frac{1}{8} \ 24x == 91 frac{5}{8} x=3frac{157}{192}$