Question

Решите уравнение (3+i)z=2-3i

Answer 1

z = (2 - 3i)/(3 + i) 
z  = (2 - 3i)(3 - i) / (3 + i)( 3 - i)
z = (6 - 2i - 9i + 3i^2) / (9 - i^2) 
z = (6 - 11i - 3) / (9 + 1)
z = (3 - 11i)/10 
z = 3/10 - 11i/10
z = 0,3 - 1,1i