Question

Найдите произведение корней уравнения: (3x+1)(2x^2+x-3)=0

Answer 1

(3x + 1)(2x^2 + x - 3) = 0

1) 3x + 1 = 0 
3x = - 1
x1 = - 1/3

2) 2x^2 + x - 3 = 0 
D = 1 + 24 = 25
x2 = ( - 1 + 5)/4 = 1
x3 = ( - 1 - 5)/4 = - 3/2 = - 1,5

x1*x2*x3 = (-1/3)*1*(-3/2) = 0,5