Question

Прошу помощи в решении.

Answer 1

4. а) 3х²+12ху+12у² = 3(х²+4ху+4у²) = 3(х+2у)² = 3(х+2у)(х+2у)

б) 8а(b-3)+c(3-b) = 8a(b-3)-c(b-3) = (b-3)(8a-c)

в) х²+3х-2ху-6у = х(х+3)-2у(х+3) = (х+3)(х-2у)