Предмет: Химия, автор: sneg11

какая масса гидроксида натрия образуется при взаимодействии 6,2 г оксида натрия с водой?

Ответы

Автор ответа: Аноним

Na2O + H2O = 2NaOH

n(Na2O) = 6.2/62=0.1 моль

n(NaOH) = 0.2 моль - по условию

m(NaOH) = 0.2*40=8 г

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