Question

Решите уравнения . пожалуйста

Answer 1

a) (3x–1)(5x+4)–15x^2=17
15x^2+12x–5x–4–15x^2=17
7x=21
x=3

б) (1–2х)(1–3х)=(6х–1)х–1
1–3х–2х+6х^2=6х^2–х–1
-4х=0
х=0

в) 12–х(х–3)=(6–х)(х+2)
12–х^2+3х=6х+12–х^2–2х
-х=0
х=0

г) (х+4)(х+1)=х–(х–2)(2–х)
х^2+х+4х+4=х–2х+х^2+4–2х
8х=0
х=0