Question

Log2 0,2/log8 50- log8 0,5

Answer 1

$frac{log_20,2}{log_850-log_80,5}=frac{log_25^{-1}}{frac{1}{3}log_2(5^2cdot 2)-frac{1}{3}log_22^{-1}}=frac{-log_25}{frac{2}{3}log_25+frac{1}{3}+frac{1}{3}} =\\=- frac{log_25}{frac{2}{3}(log_25+1)} =-frac{3cdot log_25}{2cdot (log_25+1)}$