Question

lim x---> 6 2x 3-2x 2/5x 3-4x 2

Answer 1

$displaystyle lim_{n to 6} frac{2x^3-2x^2}{5x^3-4x^2}= lim_{n to 6} frac{2x^2(x-1)}{x^2(5x-4)}= lim_{n to 6} frac{2(x-1)}{(5x-4)}= frac{2(6-1)}{5*6-4}= frac{5}{13}$