Question

Решите уравнение:
2x(x−16)^2−x^2(x−16)=0
x^1=
x^2=
x^3=

Answer 1

$2x(x-16)^2-x^2(x-16)=0 x*(x-16)*(2(x-16)-x)=0 x*(x-16)*(2x-2*16-x)=0 x*(x-16)*(2x-32-x)=0 x*(x-16)*(x-32)=0 x=0 x-16=0 x-32=0 x=0 x-16+16=0+16 x-32+32=0+32 x1=0 x2=16 x3=32$