Question

3/8⋅y−8=−16+y/8(найдите корни уравнения)

Answer 1

$(3/8)*y-8=-16+(y/8) 8*(3/8)y-8*8=-8*16+8*(y/8) 3y-(8*8)=-(8*16)+y 3y-64=-128+y 3y-y-64+64=-128+64+y-y 3y-y=-128+64 3y-1y=-(128-64) (3-1)y=-64 2y=-64 y=-32$