Question

4x^2+4x-3=0
Плиз помогите решить

Answer 1

$4 {x}^{2} + 4x - 3 = 0 \ d = {b}^{2} - 4ac = 16 - 4 times 4 times ( - 3)) = 16 + 48 = 64 = {8}^{2} \ x = frac{ - b + sqrt{d} }{2a} \ x1 = frac{ - 4 + 8}{8} = 0.5 \ x2 = frac{ - 4 - 8}{8} = - frac{12}{8} = - 0.45$