Question

(4x-6)>=(6x-4)^2
решите неравенство пожалуйста

Answer 1

$(4x-6) geq (6x-4)^2 4x-6-(6x-4)^2 geq 0 4x-6-(36x^2-48x+16) geq 0 4x-6-36x^2+48x-16 geq 0 52x-22-36x^2 geq 0 2(26x-11-18x^2) geq 0 26x-11-18x^2 geq 0 -18x^2+26x-11 geq 0 -18x^2+26x-11=0 -18x^2+26x-11 geq 0, a=-18$

x∉R

Ответ:x∈∅