Question

a) (x-3)^2>x(x-6)
б)y^2+1>2(5y-12)
докажите неравенство

Answer 1

а)x^2-6x+9>x^2-6x
x^2-6x+9-x^2+6x>0
x>-9
б)y^2+1>2 (5y-12)
y^2+1>10y-24
y^2-10y+25=0
D=10^2-4*1*25=100-100=0
y=10÷2=5