Question

решите пожалуйста$x^{2}-3 x +1 leq 0$

Answer 1

$x^2-3x+1 leq 0 \ x^2-3x+1=0 \ D=9-4=5 \ x_{1} =(3+sqrt{5})/2; x_{2}=(3-sqrt{5})/2$
$x[(3-sqrt{5})/2;(3+sqrt{5})/2]$