Предмет: Математика, автор: Аноним

》,《 - больше либо равно
Решите неравенства пж:
x>10
11+1/9z ≥5

35-5x<0
60 ≥5-13x

9,5-11《11,5x+3
29x+4 1/4 ≥33x+3 1/3

49-3(3-2z)《1-4z
-0,5(8x+9)-0,9>4x-3

Ответы

Автор ответа: keevie
0
1)  left { {{x textgreater  10} atop {11+frac{1}{9}x geq 5 }} right.
    left { {{x textgreater  10} atop {9*11+9*frac{1}{9}x geq 9*5 }} right.
    left { {{x textgreater  10} atop {99+x geq 45}} right.
    left { {{x textgreater  10} atop {x geq 45-99}} right.
    left { {{x textgreater  10} atop {x geq -54}} right.
   x∈(10, +∞)
2)  left { {{35-5x textless  0} atop {60 geq 5-13x}} right.
     left { {{-5x textless  -35} atop {13x geq 5-60}} right.
     left { {{x textgreater  7} atop {13x geq -55}} right.
     left { {{x textgreater  7} atop {x geq - frac{55}{13}}} right.
    x∈(7, +∞)
3)  left { {{9.5-11 leq 11.5x+3} atop {29x+4frac{1}{4} geq 33x+3frac{1}{3}}} right.
     left { {{-1.5 leq 11.5x+3} atop {29x+frac{17}{4} geq 33x+frac{10}{3}}} right.
     left { {{-11.5x leq 3+1.5} atop {29x-33x geq frac{10}{3}-frac{17}{4} }} right.
     left { {{-11.5x leq 4.5} atop {-4x geq frac{40-51}{12} right.
     left { {{x geq -4.5:11.5} atop {-4x geq -frac{11}{12} right.
     left { {{x geq - frac{45}{10}:frac{115}{10}} atop {xleqfrac{11}{48}} right.
     left { {{x geq - frac{45}{10}*frac{10}{115}} atop {xleqfrac{11}{48}} right.
     left { {{x geq - 9*frac{1}{23}} atop {xleqfrac{11}{48}} right.
     left { {{x geq -frac{9}{23}} atop {xleqfrac{11}{48}} right.
    x∈[-frac{9}{23}, frac{11}{48}]
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