Question

Решить уравнение:

tgx = 1/√3

Answer 1

tgx=1/√3

x=arctg1/√3+πn , n∈Z

x=π/6+πn , n∈Z

 

 

 

 

Answer 2

$tgx=frac{1}{sqrt3} \ \ x=arctg(frac{1}{sqrt3})+pi n, n in Z \ \ x=frac{pi}{6}+pi n, n in Z$