Question

Помогите,предел найти

Answer 1

$lim_{x to pi/6} dfrac{(2sin x-1)(sin x+1)}{(2sin x - 1)(sin x-1)}= lim_{xto pi/6}frac{sin x+1}{sin x-1}=frac{3/2}{-1/2}=-3$

Ответ: - 3