Question

ПОМОГИТЕ СРОЧНО
решите уравнение -√8 sin2x+2=0

Answer 1

$- sqrt{8} sin2x + 2 = 0 \ sin2x = frac{2}{sqrt{8}} \ sin2x = sqrt{frac{4}{8}} \ sin2x = frac{sqrt{2}}{2}} \ 2x = (-1)^k arcsin(frac{sqrt{2}}{2}) + pi k in Z\ 2x = (-1)^kfrac{pi}{4} + pi k, k in Z \ x = (-1)^kfrac{pi}{8} + frac{pi k}{2},kin Z$