Question

sin3x=0. tg2x=-1. 3tg^2x+2tgx-1=0 .cosx+sin(пи/2-x)+cos(пи+x)=0.

Answer 1

1)x=Пn/3
2)-П/8+Пn/2
3)tgx=t
3t^2+2t-1=0
D=16
T1=1/3
T2=-1
Tgx=1/3
X=arctg1/3+Пn
Tgx=-1
X=-П/4+Пn
4) cosx+cosx-cosx=0
Cosx=0
X=П/2+Пn