Question

Комплексные числа
(2*i-1)^4-(2*i+1)^4

Answer 1

(2i-1)^4-(2i+1)^4=((2i-1)^2-(2i+1)^2)*((2i-1)^2+(2i+1)^2)=(4i^2-4i+1-4i^2-4i-1) * (4i^2-4i+1+4i^2+4i+1)=-8i*(8i^2+2)=-8i*(-6) = 48i