Question

20+3(х-15)

16-4(2+a)

-35-12(b-3)

-18+(4-х)

42-6(7+y)

29-3(t-8)

Answer 1

20+3(х-15)=20+3х-45=3х-25

16-4(2+a)=16-8-4а=8-4а

-35-12(b-3)=-35-12b+36=1-12b

-18+(4-х)=-18+4-х=-14-х

42-6(7+y)=42-42-6у=-6у

29-3(t-8)=29-3t+24=53-3t