Question

Помогите решить пожалуйста..

Answer 1

1.

$y' = (frac{2}{3}x^3 - x^2 - 4x + 5)' =(frac{2}{3}x^3)' - (x^2)' - (4x)' + (5)' =$$= 2x^2 - 2x - 4 = 2(x^2 - x - 2)$

2.
$y = x^3(2x - 1) = 2x^4 - x^3$

$y' = (2x^4 - x^3)' = 8x^3 - 3x^2$