Question

Решите уравнение
(3+i)z=2-3i

Answer 1

z = (2 - 3i)/(3 + i)
z = (2 - 3i)(3 - i)/(3 + i)(3 - i)
z = (6 - 2i - 9i + 3i^2) / (9 - i^2) 
z = (6 - 11i - 3)/(9 + 1) 
z = (3 - 11i)/10
z = 0,3 - 1,1i