Question

Решите уравнения:
1)16x³-8x²+x=0
2)x³+2x²-36x-72=0

Answer 1

1) х(16х² - 8х + 1 ) = 0
х(4х- 1)² = 0
1.х = 0
2.4х-1 = 0
4х = 1
х = 0.2

2) х² ( х + 2) - 36 (х+2) = 0
(х² - 36) ( х+2) = 0
(х - 6) (х+6) (х+2) = 0
1.х-6 = 0
х=6
2. х+6=0
х=-6
3. х+2=0
х=-2