Предмет: Алгебра, автор: anka890

ctg(п-l)ctg(3п/2+l)-tg(2п+l)ctg(п/2+l)

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Автор ответа: Эксперт5

0

ctg(π-a)ctg(3π/2+a)-tg(2π+a)ctg(π/2+a)=
=-ctga*(-tga)-tga*(-tga)=1+tg²a=1/cos²a

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