Предмет: Алгебра,
автор: tanyatimchenko
2log(1/3)6 - 1/2log(1/3)400 + 3log(1/3) ³√45
Ответы
Автор ответа:
0
2log(1/3)6 - 1/2log(1/3)400 + 3log(1/3) ³√45 =
= log (1/3)6^2 - log(1/3)√(400) + log(1/3)(∛45)^3 =
= log(1/3) 36 - log (1/3) 20 + log(1/3) 45 =
= log (1/3) (36/20) + log (1/3) 45 =
= log (1/3) (9/5) + log (1/3) 45 =
= log (1/3) ((9*45)/5) =
= log (1/3) 81 =
= log 3^(-1) 3^4 =
= - log 3 3^4 = - 4
= log (1/3)6^2 - log(1/3)√(400) + log(1/3)(∛45)^3 =
= log(1/3) 36 - log (1/3) 20 + log(1/3) 45 =
= log (1/3) (36/20) + log (1/3) 45 =
= log (1/3) (9/5) + log (1/3) 45 =
= log (1/3) ((9*45)/5) =
= log (1/3) 81 =
= log 3^(-1) 3^4 =
= - log 3 3^4 = - 4
Похожие вопросы
Предмет: Математика,
автор: studyolesya
Предмет: История,
автор: sodoma19499
Предмет: Українська мова,
автор: andrej999
Предмет: Геометрия,
автор: kamyshkagolda
Предмет: Физика,
автор: Danon1122