Question

номер 965 помогите решить!!

Answer 1

1)(x/2+y/3)*6=(3x+2y)/6*6=3x+2y=3*4+2*(-1)=12-2=10
2)(x/4-y/12)*12=(3x-y)/12*12=3x-y=3*(-2)-3=-6-3=-9
3)(2x/3+y/5)*3=(10x+3y)/15*3=(10x+3y)/5=(10*1+3*2)/5=(10+6)/5=16/5=3,2
4)(5x/6-3y/8)*4=(40x-18y)/48*4=(40x-18y)/12=(40*6-18*2)/12=204/12=17