Question

Решите систему уравнений
x^2-y^2=12
x+y/x-y=3

Answer 1

x≠y
x+y=3(x-y)
x²-y²=12
(x-y)(x+y)=12
3(x-y)²=12
!x-y!=2
1/ x-y=2
x+y=6
2x=8
x=4
y=2
2/ x-y=-2
x+y=-6
2x=-8
x=-4
y=-2
(4 2 )(-4 -2)