Question

представьте в виде произведения 16-(2n^2+4)^2

Answer 1

$16-(2n^2+4)^2=4^2-(2n^2+4)^2=(4-(2n^2+4))(4+2n^2+4)= \=(4-2n^2-4)(8+2n^2)=-2n^2(8+2n^2)=-4n^2(4+n^2)$