Question

(4a+c)3=
(m2+2ac)3=
(x-y)3=

Answer 1

1) (4a+c)³=(4a)³+3·(4a)²·c+3·4ac²+c³=64a³+3·16a²+12ac²+c³=64a³+48a²c+12ac²+c³.
2) (m²+2ac)³=(m²)³+3·(m²)²·2ac+3m²·(2ac)²+(2ac)³=m⁶+3m⁴·2ac+3m²·4a²c²+8a³c³=m⁶+6acm⁴+12a²c²m²+8a³c³.
3) (x-y)³=x³-3x²y+3xy²-y³.

Answer 2

Спасибо