Question

решите уравнение: 1) x+4 4/19=6 2/19; 2)25-x =8 3/14; 3) 32-x=9 18/35. дам 60 баллов

Answer 1

$displaystyle tt 1) : x+4frac{4}{19}=6frac{2}{19}\displaystyle tt x+frac{80}{19}=frac{116}{19}\displaystyle tt x=frac{116}{19}-frac{80}{19}\displaystyle tt x=frac{36}{19}\displaystyle tt boxed{bold{x=1frac{17}{19}}}$

$displaystyle tt 2) : 25-x=8frac{3}{14}\displaystyle tt 25-x=frac{115}{14}\displaystyle tt -x=frac{115}{14}-25\displaystyle tt -x=-frac{235}{14}\displaystyle tt x=frac{235}{14}\displaystyle tt boxed{bold{x=16frac{11}{14}}}$

$displaystyle tt 3) : 32-x=9frac{18}{35}\displaystyle tt 32-x=frac{333}{35}\displaystyle tt -x=frac{333}{35}-32\displaystyle tt -x=-frac{787}{35}\displaystyle tt x=frac{787}{35}\displaystyle tt boxed{bold{x=22frac{17}{35}}}$