Question

Решите уравнение 3х^2-0,5=0
(4-2x)^2=3x-6
2x^3-x^2+6x-3=0

Answer 1

$3x^2-0,5=0\ 3x^2=0,5\ x^2= frac{1}{6} \ x=pm frac{ sqrt{6} }{6} \ \ (4-2x)^2=3x-6\ 16-16x+4x^2=3x-6\ 4x^2-16x-3x+16+6=0\ 4x^2-19x+22=0\ D=19^2-4*4*22=361-352=9 x_1= frac{19+3}{8} = frac{11}{4} =2,75\ x_2= frac{19-3}{8} =2\ \ 2x^3-x^2+6x-3=0\ (2x^3+6x)-(x^2+3)=0\ 2x(x^2+3)-(x^2+3)=0\ (2x-1)(x^2+3)=0\ 2x-1=0, x=0,5\ x^2+3=0, x^2 neq -3$