Question

Решите уравнение
1) x^(2)-49=0
2)(x-3)^(2)-(x+1)^(2)=12

Answer 1

$1) x^{2}-49=0 \ \ (x-3)(x+3)=0 \ \ x_1=3 \ x_2=-3 \ \ 2) (x-3)^{2}-(x+1)^{2}=12 \ \ (x-3-x-1)(x-3+x+1)=12 \ \ -4(2x-2)=12 \ 2x-2=-3 \ 2x=-1 \ x=-1/2=-0.5$