Question

 Плиз помогите!!!!!) Решите неравенство: (9-x^2)/(3x+1)>=2/x

Answer 1

(9-x^2)/(3x+1)>=2/x

ODZ

3x+1=0

3x=-1

x=-1/3(ne mojet but')

x=0(ne mojet but')

(x(9-x^2))/(3x+1)-(2*(9-x^2))/x>=0

9x-x^3-6x+2>=0

x^3-3x+2>=0

x^3-3x+2=0

((x-1)^2)*(x+2)

(x-1)^2=0

D=0

x=1;

x+2=0

x=-2

(-beskone4nostu;-2]U(-1/3;+beskone4nostu)