Question

5d^4-15d^2/48d-16d^3 при d=-18,4,d=18,4

Answer 1

$frac{5d^4-15d^2}{48d-16d^3}=frac{5d(d^2-3)}{16(3-d^2)}=-frac{5d}{16}=-frac{б18,4*5}{16}=б5,75$