Question

Прошу помогите! (y^3+2)^3-y^6(y^3-6)+2(y-2)^2 при y=-2

Answer 1

$(y^3+2)^3-y^6(y^3-6)+2(y-2)^2=((-2)^3+2)^3-(-2)^6((-2)^3-6)+\ +2(-2-2)^2=(-8+2)^3-64(-8-6)+2(-4)^2=(-6)^3-64(-14)+\ +32=-216+896+32=712$